关于因式分解的题目,要过程
5个回答
展开全部
16(x-y)²-25(x+y)²
=[4(x+y)]²-[5(x-y)]²
=(4x+4y+5x-5y)(4x+4y-5x+5y)
=(9x-y)(-x+9y)
25(a-2b)³+4(2b-a)
=25(a-2b)³-4(a-2b)
=(a-2b)[25(a-2b)²-4]
=(a-2b)[5(a-2b)+2][5(a-2b)-2]
=(a-2b)(5a-10b+2)(5a-10b-2)
(2m-n)²-(2m+2n)²
=4m²-4mn+n²-4m²-8mn-4n²
=-3n²-12mn
=3n(-1-4m)
(x-y+2z)²-(x-2y-3z)²正在算
=[4(x+y)]²-[5(x-y)]²
=(4x+4y+5x-5y)(4x+4y-5x+5y)
=(9x-y)(-x+9y)
25(a-2b)³+4(2b-a)
=25(a-2b)³-4(a-2b)
=(a-2b)[25(a-2b)²-4]
=(a-2b)[5(a-2b)+2][5(a-2b)-2]
=(a-2b)(5a-10b+2)(5a-10b-2)
(2m-n)²-(2m+2n)²
=4m²-4mn+n²-4m²-8mn-4n²
=-3n²-12mn
=3n(-1-4m)
(x-y+2z)²-(x-2y-3z)²正在算
更多追问追答
追问
第三题题目写错了吧。是(3m+2n)
追答
sorry
展开全部
1、原式
=[4(x-y)]²-[5(x+y)]²
=[4(x-y)+5(x+y)][4(x-y)-5(x+y)]
=(9x+y)(-x-9y)
=-(9x+y)(x+9y)
2、原式
=(a-2b){[5(a-2b)]²-4}
=(a-2b)(5a-10b+2)(5a-10b-2)
=[4(x-y)]²-[5(x+y)]²
=[4(x-y)+5(x+y)][4(x-y)-5(x+y)]
=(9x+y)(-x-9y)
=-(9x+y)(x+9y)
2、原式
=(a-2b){[5(a-2b)]²-4}
=(a-2b)(5a-10b+2)(5a-10b-2)
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展开全部
1、原式=[4(x-y)+5(x+y)][4(x-y)-5(x+y)]
=(4x-4y+5x+5y)(4x-4y-5x-5y)
=(9x+y)(-x-9y)
=-(9x+y)(x+9y)
=(4x-4y+5x+5y)(4x-4y-5x-5y)
=(9x+y)(-x-9y)
=-(9x+y)(x+9y)
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