求数学大神 这个题怎么做 求过程
3个回答
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为了易懂,先只写分子的部分。
(3^(5/4))x(15^(3/4))=(3^(5/4))x((3x5)^(3/4))
=(3^(5/4))x(3^(3/4))x(5^(3/4))
=(3^(5/4+3/4))x(5^(3/4))
=(3^2)x(5^(3/4));
分母的部分:
(5^(-3/4))x(45^(-1/2))=(5^(-3/4))x((5x9)^(-1/2))
=(5^(-3/4))x(5^(-1/2))x(9^(-1/2)
=(5^(-3/4-1/2))x(3^(2x(-1/2))
=(5^(-5/4))x(3^(-1))
分子/分母=((3^2)x(5^(3/4)))x((5^(5/4))x(3^(1)))
=(3^(2+1))x(5^(3/4+5/4))
=(3^3)x(5^2)=27x25=675
(3^(5/4))x(15^(3/4))=(3^(5/4))x((3x5)^(3/4))
=(3^(5/4))x(3^(3/4))x(5^(3/4))
=(3^(5/4+3/4))x(5^(3/4))
=(3^2)x(5^(3/4));
分母的部分:
(5^(-3/4))x(45^(-1/2))=(5^(-3/4))x((5x9)^(-1/2))
=(5^(-3/4))x(5^(-1/2))x(9^(-1/2)
=(5^(-3/4-1/2))x(3^(2x(-1/2))
=(5^(-5/4))x(3^(-1))
分子/分母=((3^2)x(5^(3/4)))x((5^(5/4))x(3^(1)))
=(3^(2+1))x(5^(3/4+5/4))
=(3^3)x(5^2)=27x25=675
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