3个回答
展开全部
-X³+3X-2
=-X³+X²-X²+3X-2
=-X²(X-1)-(X²-3X+2)
=-X²(X-1)-(X-1)(X-2)
=-(X-1)(X²+X-1)
=-X³+X²-X²+3X-2
=-X²(X-1)-(X²-3X+2)
=-X²(X-1)-(X-1)(X-2)
=-(X-1)(X²+X-1)
追答
-X³+3X-2
=-X³+X²-X²+3X-2
=-X²(X-1)-(X²-3X+2)
=-X²(X-1)-(X-1)(X-2)
=-(X-1)(X²+X-2)
=-(X-1)²(X+2)
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展开全部
原式
=(1-x³)+(3x-3)
=(1-x³)-3(1-x)
=(1-x)(x²+x+1)-3(1-x)
=(1-x)(x²+x+1-3)
=(1-x)(x²+x-2)
=-(1-x)²(x+2)
=(1-x³)+(3x-3)
=(1-x³)-3(1-x)
=(1-x)(x²+x+1)-3(1-x)
=(1-x)(x²+x+1-3)
=(1-x)(x²+x-2)
=-(1-x)²(x+2)
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