Question

51单片机函数效果的跳转

#include "reg52.h"
unsigned char Count;
sbit _Speak =P1^5 ;
unsigned char code SONG[] ={ //祝你平安
0x26,0x20,0x20,0x20,0x20,0x20,0x26,0x10,0x20,0x10,0x20,0x80,0x26,0x20,0x30,0x20,
0x30,0x20,0x39,0x10,0x30,0x10,0x30,0x80,0x26,0x20,0x20,0x20,0x20,0x20,0x1c,0x20,
0x20,0x80,0x2b,0x20,0x26,0x20,0x20,0x20,0x2b,0x10,0x26,0x10,0x2b,0x80,0x26,0x20,
0x30,0x20,0x30,0x20,0x39,0x10,0x26,0x10,0x26,0x60,0x40,0x10,0x39,0x10,0x26,0x20,
0x30,0x20,0x30,0x20,0x39,0x10,0x26,0x10,0x26,0x80,0x26,0x20,0x2b,0x10,0x2b,0x10,
0x2b,0x20,0x30,0x10,0x39,0x10,0x26,0x10,0x2b,0x10,0x2b,0x20,0x2b,0x40,0x40,0x20,
0x20,0x10,0x20,0x10,0x2b,0x10,0x26,0x30,0x30,0x80,0x18,0x20,0x18,0x20,0x26,0x20,
0x20,0x20,0x20,0x40,0x26,0x20,0x2b,0x20,0x30,0x20,0x30,0x20,0x1c,0x20,0x20,0x20,
0x20,0x80,0x1c,0x20,0x1c,0x20,0x1c,0x20,0x30,0x20,0x30,0x60,0x39,0x10,0x30,0x10,
0x20,0x20,0x2b,0x10,0x26,0x10,0x2b,0x10,0x26,0x10,0x26,0x10,0x2b,0x10,0x2b,0x80,
0x18,0x20,0x18,0x20,0x26,0x20,0x20,0x20,0x20,0x60,0x26,0x10,0x2b,0x20,0x30,0x20,
0x30,0x20,0x1c,0x20,0x20,0x20,0x20,0x80,0x26,0x20,0x30,0x10,0x30,0x10,0x30,0x20,
0x39,0x20,0x26,0x10,0x2b,0x10,0x2b,0x20,0x2b,0x40,0x40,0x10,0x40,0x10,0x20,0x10,
0x20,0x10,0x2b,0x10,0x26,0x30,0x30,0x80,0x00};
void Time0_Init()
{
TMOD = 0x01;
IE = 0x82;
TH0 = 0xD8;
TL0 = 0xEF; //12MZ晶振，10ms
}
void Time0_Int() interrupt 1
{
TH0 = 0xD8;
TL0 = 0xEF;
Count++; //长度加1
}
void Delay_xMs(unsigned int x)
{
unsigned int i,j;
for( i =0;i < x;i++ )
{
for( j =0;j<3;j++ );
}
}
void Play_Song(unsigned char i)
{
unsigned char Temp1,Temp2;
unsigned int Addr;
Count = 0; //中断计数器清0
Addr = i * 217;
while(1)
{
Temp1 = SONG[Addr++];
if ( Temp1 == 0xFF ) //休止符
{
TR0 = 0;
Delay_xMs(100);
}
else if ( Temp1 == 0x00 ) //歌曲结束符
{
return;
}
else
{
Temp2 = SONG[Addr++];
TR0 = 1;
while(1)
{
_Speak = ~_Speak;
Delay_xMs(Temp1);
if ( Temp2 == Count )
{
Count = 0;
break;
}
}
}
}
}
void main()
{
Time0_Init(); //定时器0中断初始化
while(1)
{
Play_Song(0); //播放
}
}

这个程序加两个按键，按键1控制这个程序，按键2控制另一个，这个程序在哪修改可以做到在曲子没放完的时候按按键2就马上跳转到按键2的函数效果

求帮忙！！！

Answer 1

如果你说的是按键1控制播放这一首歌，按键2控制播放另外一首歌，这是可以实现的，但如果控制区执行另外一个程序，那有点难度。你最好的解决办法就是将两个程序合并。

追问

对，按键1控制这首歌，按键2控制的8*8点阵屏，这个程序该怎么改能告诉我吗
最主要的是，这个程序在哪修改可以做到在曲子没放完的时候按按键2就马上跳转到按键2的点阵屏

追答

在播放音乐的子程序中检测按键2就可以实现这个功能了。