Question

C语言编程中如何求100以内的自然数中奇数之和？

Answer 1

//编译通过#include <stdio.h>
void main()
{
int nSum = 1;
for (int i=2; i<=100; i++)
{
if (i%2 != 0)
{
nSum += i;
}
}
printf("0~100的奇数之和为：%d\n", nSum);
}