Question

求这道打勾的高数题的详细解答过程，谢谢

求定积分

Answer 1

如图所示

Answer 2

let
u=√(1-x)
-2udu = dx
x=3/4 , u= 1/2
x=1, u=0
∫(3/4->1) dx/[√(1-x) -1]
=∫(1/2->0) -2udu/(u -1)
=-2∫(1/2->0) [ 1 + 1/(u -1)] du
= -2[ u +ln|u-1|]|(1/2->0)
=2[ 1/2 + ln(1/2) ]
=1 - 2ln2