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arctanx +arctan(1/x) = π/2
u=-x
du =-dx
I
=∫(-π/4->π/4) 5sinx. [e^x/(1+e^(2x)] dx
=∫(π/4->-π/4) -5sinu. [e^(-u)/(1+e^(-2u)] ( -du)
=∫(-π/4->π/4) -5sinx. [e^(-x)/(1+e^(-2x)] dx
=∫(-π/4->π/4) -5sinx. [e^(x)/(1+e^(2x)] dx
2I=∫(-π/4->π/4) 5sinx. [e^x/(1+e^(2x)] dx+∫(-π/4->π/4) -5sinx. [e^(x)/(1+e^(2x)] dx
=0
I=0
u=-x
du =-dx
I
=∫(-π/4->π/4) 5sinx. [e^x/(1+e^(2x)] dx
=∫(π/4->-π/4) -5sinu. [e^(-u)/(1+e^(-2u)] ( -du)
=∫(-π/4->π/4) -5sinx. [e^(-x)/(1+e^(-2x)] dx
=∫(-π/4->π/4) -5sinx. [e^(x)/(1+e^(2x)] dx
2I=∫(-π/4->π/4) 5sinx. [e^x/(1+e^(2x)] dx+∫(-π/4->π/4) -5sinx. [e^(x)/(1+e^(2x)] dx
=0
I=0
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