Question

输入正整数a,b,c,输出a/b的小数形式，精确到小数点后c位。C/C++编程实现

Answer 1

#include<stdio.h>

int main(void)
{
int a, b, c;
printf("Please input a b c : ");
scanf("%d%d%d", &a, &b, &c);
switch(c)
{
case 0:
printf("a/b = %.f",(float)a/b);
break;
case 1:
printf("a/b = %.1f",(float)a/b);
break;
case 2:
printf("a/b = %.2f",(float)a/b);
break;
case 3:
printf("a/b = %.3f",(float)a/b);
break;
case 4:
printf("a/b = %.4f",(float)a/b);
break;
case 5:
printf("a/b = %.5f",(float)a/b);
break;
case 6:
printf("a/b = %.6f",(float)a/b);
break;
default:
printf("error!");
break;
}
return 0;
}
没细想，抛砖引玉吧。

Answer 2

用c++实现的，完全符合要求,可以手动输入a,b,c的值。
————————————————
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
int a,b,c;
cout<<"Input a, b: ";
cin>>a>>b;
cout<<"Input c:";
cin>>c;
cout<<setprecision(c);
cout<<(double)a/b<<endl;
return 0;
}
————————————————

Answer 3

printf("%.cf",a/b);