
2个回答
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(A^2-B^2+2B-1)/(A^2-B^2)+(A+B)
=[A^2-(B-1)^2/(A+B)(A-B)]+A+B
=(A+B-1)(A-B-1)/(A+B)(A-B+1)
=A+B+1/(A+B)
=2009+1/2009
=2010/2009
=[A^2-(B-1)^2/(A+B)(A-B)]+A+B
=(A+B-1)(A-B-1)/(A+B)(A-B+1)
=A+B+1/(A+B)
=2009+1/2009
=2010/2009
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