
2个回答
展开全部
a^2+b^2-a^2b^2-4ab-1
=a^2-2ab+b^2-a^2b^2-2ab-1
=(a^2-2ab+b^2)-(a^2b^2+2ab+1)
=(a-b)^2-(ab+1)^2
=(a-b+ab+1)(a-b-ab-1)
=a^2-2ab+b^2-a^2b^2-2ab-1
=(a^2-2ab+b^2)-(a^2b^2+2ab+1)
=(a-b)^2-(ab+1)^2
=(a-b+ab+1)(a-b-ab-1)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询