Question

(a+b/2ab^2)^3/(a^2-b^2/ab^2)^2/{1/2(a-b)}^2,其中a=-1/2,b=2/3

我需要过程。OK？

Answer 1

解：原式=[(a+b)^3/(8a^3b^6)*(1/4)*(a-b)^2]/{[(a+b)^2(a-b)^2]/(a^2b^4)}
=[(a+b)/8a^3b^6]*a^2b^4*(1/4)
=1/32(a+b)/(ab^2)
=1/32×(-1/2+2/3)/[(-1/2)*(4/9)]
=-3/128

Answer 2

1，|2a-1|+4a^2-4ab+b^2=0,则2a-1=0,2a-b=0.
a=1/2,b=1代入
a^2(a-b)+2ab(a-b)+ab^2-b^3自己求
2，还要问题