Question

初一数学题 计算的 要过程

(1） (0.04)^2009乘[(-5)^2009]^2
(2) (1-1/2)^2(1-1/3)^2(1-1/4)^2·……·(1-1/10)^2

Answer 1

(0.04)^2009*[(-5)^2009]^2
=(0.04)^2009*(-5)^2009*(-5)^2009
=(0.04*(-5))^2009*(-5)^2009
=(-0.2)^2009*(-5)^2009
=(-0.2*(-5))^2009
=1^2009
=1

(1-1/2)^2(1-1/3)^2(1-1/4)^2·……·(1-1/10)^2
=((1-1/2)(1-1/3)(1-1/4)……(1-1/10))^2
=(1/2*2/3*3/4*……9/10)
=(1/10)^2
=1/100

Answer 2

（1） (0.04)^2009*[(-5)^2]^2009
= (0.04)^2009*25^2009
=（0.04*25）^2009
=1^2009
=1

（2）原式=[（1/2）（2/3）（3/4）......（9/10）]^2
=(1/10)^2
=1/100

Answer 3

(1） (0.04)^2009乘[(-5)^2009]^2
＝〔0。04＊（－5）＊（－5）〕^2009
=(1)^2009
=1
(2) (1-1/2)^2(1-1/3)^2(1-1/4)^2·……·(1-1/10)^2
=[(1/2)*(2/3)*(3/4)....*(9/10)]^2
=(1/10)^2
=1/100

Answer 4

(1) (0.04)^2009X[(-5)^2009]^2=(0.04)^2009X[(-5)^2]^2009=[0.04X25]^2009=1
(2) (1-1/2)^2(1-1/3)^2(1-1/4)^2·……·(1-1/10)^2
=(1/2)^2(2/3)^2(3/4)^2·……·(9/10)^2
=[(1/2)(2/3)(3/4)·……·(9/10)]^2
=[1/1O]^2
=0.01

Answer 5

(1)
=（0.04）^2009乘[（-5）^2]^2009
=(0.04乘25)^2009
=1
(2)
=[(1-1/2)(1-1/3)(1-1/4)^2·……·(1-1/10)]^2
=……自己减了展开就发现很多都能约掉
=1/100
记得给分