Question

初二数学题，要详细过程，一定要详细！好的加分，急

计算：（4x²-y²）÷4x²-4xy+y²/2x-y

Answer 1

解：（4x²-y²）÷4x²-4xy+y²/2x-y
=（4x²-y²）*（1/4x²）-4xy+y²/2x-y
=1-y²/4x²-4xy+y²/2x-y
=1-4xy-y+y²/2x-y²/4x²
=1-4xy-y+(y²*2x)/(2x*2x)-y²/4x²
=1-4xy-y+2xy²/4x²-y²/4x²
=1-4xy-y+(2x-1)*y²/4x²
本题有点问题，题目应该是化简或者是告诉x y的值，再计算！]
希望我做的对你有点帮助。

Answer 2

∵4x2-y2=(2x+y)(2x-y)
4x2-4xy+y2=(2x-y)2
∴4x2-4xy+y2/2x-y=2x-y
∴原式=(2x+y)(2x-y)/2x-y=2x+y