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初二分式加减
利用n分之1乘n+1分之1=n分之1-(n+1)分之1这个等式计算:(x-2)(x-3)分之1-(x-1)(x-3)分之2+(x-1)(x-2)分之1...
利用n分之1乘n+1分之1=n分之1- (n+1)分之1这个等式计算:(x-2)(x-3)分之1- (x-1)(x-3)分之2+ (x-1)(x-2)分之1
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解:1/(x-2)(x-3)- 2/(x-1)(x-3)+1/ (x-1)(x-2)
=1/(x-3)-1/(x-2)-1/(x-3)+1/(x-1)+1/(x-2)-1/(x-1)-\
=0
=1/(x-3)-1/(x-2)-1/(x-3)+1/(x-1)+1/(x-2)-1/(x-1)-\
=0
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