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a=2x²-3x+1
11a=22x²-33x+11
所以原式=a²-11a+10
=(a-1)(a-10)
=(2x²-3x+1-1)(2x²-3x+1-10)
=x(2x-3)(2x+3)(x-3)
(x+y-2XY)(x+y-2)+(xy-1)^2
=[(x+y)-2xy][(x+y)-2]+(xy-1)²
=(x+y)²-2(xy+1)(x+y)+4xy+x²y²-2xy+1
=(x+y)²-2(xy+1)(x+y)+x²y²+2xy+1
=(x+y)²-2(xy+1)(x+y)+(xy+1)²
=[(x+y)-(xy+1)]²
=(x+y-xy-1)²
=[x(1-y)-(1-y)]²
=(x-1)²(1-y)²
=(x-1)²(y-1)²
11a=22x²-33x+11
所以原式=a²-11a+10
=(a-1)(a-10)
=(2x²-3x+1-1)(2x²-3x+1-10)
=x(2x-3)(2x+3)(x-3)
(x+y-2XY)(x+y-2)+(xy-1)^2
=[(x+y)-2xy][(x+y)-2]+(xy-1)²
=(x+y)²-2(xy+1)(x+y)+4xy+x²y²-2xy+1
=(x+y)²-2(xy+1)(x+y)+x²y²+2xy+1
=(x+y)²-2(xy+1)(x+y)+(xy+1)²
=[(x+y)-(xy+1)]²
=(x+y-xy-1)²
=[x(1-y)-(1-y)]²
=(x-1)²(1-y)²
=(x-1)²(y-1)²
来自:求助得到的回答
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