Question

ab的平方=-1,求-ab(a的平方b的五次方-ab的3次方-b)

Answer 1

ab^2=-1
-ab(a^2b^5-ab^3-b)
= -ab{ a^2b^4 * b - ab^2 * b - b)
= -ab{ (-1)^2 * b - (-1) * b - b)
= -ab{ b + b - b)
= -ab^2
= 1

Answer 2

(a-b)的5次方*(b-a)的4次方*(b-a)
=（a-b)^(5+4+1)*(-1)=-(a-b)^10
2、已知2的n次方=5，2的m次方=7，
2^(m+2n)=2^m*2^(2n)=7*25=175
3、已知n+2m=3,
2的n+1次方*2的m-1次方*2的n-1次方*2的3m+1次方=2^(n+1+m-1+n-1+3m+1)=2^(2n+4m)=9
4、若2x的2次方-5x+5=0,
（15x的2次方-18x+9）-（-3x的2次方+19x-31）-8x
=18x^2-45x+40
=9(2x^2-5x+5)-45+40
=-5

Answer 3

-ab(a^2b^5-ab^3-b)
=-ab^2(a^2b^4-ab^2-1)
=-ab^2[(ab^2)^2-ab^2-1]
=-(-1)[(-1)^2-(-1)-1]
=1+1-1
=1

Answer 4

-ab(a^2b^5-ab^3-b)
=-ab^2(a^2b^4-ab^2-1)
=-ab^2[(ab^2)^2-ab^2-1]
=-(-1)[(-1)^2-(-1)-1]
=1+1-1
=1