Question

化工翻译

Table 1 shows that (R,R)-1 and (S,S)-3 bind amino alcohols with the same sense of stereoselectivity. We suggest that folding of the complex is an important factor for determining the sense of the stereoselectivity. The stereoselectivity of (S,S)-3 increases from about 2.9 to 36.0 with increasing steric bulk of the amino alcohol
(10 > 9 > 8). In contrast, the stereoselectivity of (R,R)-1 remains low (selectivity ≈2.6) independent of the size of the amino alcohol. Since the nitrophenyl group in 3 is much bigger than the hydrogen in 1, the binding cavity should be smaller for 3. As larger amino alcohols fill the small cavity in 3, the stereoselectivity is expected
to increase.

Answer 1

这是一段有机化学的关于立体构象和结合的资料。下面是手工翻译，希望对你有帮助。
表1显示，相同立体选择性的（R,R）-1和（S,S）-3结合的氨基醇。我们猜想复合体的折叠是决定立体选择性的重要因素。随着氨基醇空间位阻升高（10>9>8）（S,S）-3的立体选择性从2.9增加到36.0。 相反，（R,R）-1的立体选择性一直很低（大约2.6），而且与氨基醇的大小无关。由于3-硝基比1-氢大得多，3位的结合腔应该更小。因为更大的氨基醇填充了3号小结合腔，立体选择性应该升高。

Answer 2

一段有机化学的关于立体构象和结合的资料。