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七年级数学计算题 急!要过程
1.(ax+b)(cx+d)2.(-3x+y)(-3x-y)3.(x+2)(x-1)-(x-2)(x+3)4.(x-2)(x的平方+2x)+(x+2)(x的平方-2x)5...
1.(ax+b)(cx+d)
2.(-3x+y)(-3x-y)
3.(x+2)(x-1)-(x-2)(x+3)
4.(x-2)(x的平方+2x)+(x+2)(x的平方-2x)
5.若(x-5)(x+20)=x的平方+mx+n,求m与n的值 展开
2.(-3x+y)(-3x-y)
3.(x+2)(x-1)-(x-2)(x+3)
4.(x-2)(x的平方+2x)+(x+2)(x的平方-2x)
5.若(x-5)(x+20)=x的平方+mx+n,求m与n的值 展开
3个回答
展开全部
1.(ax+b)(cx+d)
=ax(cx+d)+b(cx+d)
=acx2+adx+bcx+bd
=acx平方+(ad+bc)x+bd
2.(-3x+y)(-3x-y)
=(3x-y)(3x+y)
=9x平方+y平方
3.(x+2)(x-1)-(x-2)(x+3)
=x平方+x-2-(x平方+x-6)
=4
4.原式=x(x+2)(x-2)+x(x+2)(x-2)
=2x(x+2)(x-2)
5.因为(x-5)(x+20)=X平方+15x-100
=x平方+mx+n
所以m=15,n=-100
=ax(cx+d)+b(cx+d)
=acx2+adx+bcx+bd
=acx平方+(ad+bc)x+bd
2.(-3x+y)(-3x-y)
=(3x-y)(3x+y)
=9x平方+y平方
3.(x+2)(x-1)-(x-2)(x+3)
=x平方+x-2-(x平方+x-6)
=4
4.原式=x(x+2)(x-2)+x(x+2)(x-2)
=2x(x+2)(x-2)
5.因为(x-5)(x+20)=X平方+15x-100
=x平方+mx+n
所以m=15,n=-100
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