Question

计算a^2-b^2/a+b-4a(a-b)+b^2/2a-b

要有过程！

Answer 1

原式=(a+b)(a-b)/(a+b)-(4a^2-4ab+b^2)/(2a-b)
=a-b-(2a-b)^2/(2a-b)
=a-b-2a+b
=-a

Answer 2

原式=(3x^2+1/2y-2/3y^2)*(-1/8x^3y^3)
=3x^2*(-1/8x^3y^3)+1/2y*(-1/8x^3y^3)-2/3y^2*(-1/8x^3y^3)
=-3/8x^5y^3)-1/16x^3y^4+1/12x^3y^4