因式分解法解下列方程 1.X²-7X+6=0 2.(5X-1)²=3(5X-1) 3.(2X-5)²-(X+4)²=0
因式分解法解下列方程1.X²-7X+6=02.(5X-1)²=3(5X-1)3.(2X-5)²-(X+4)²=0...
因式分解法解下列方程
1.X²-7X+6=0
2.(5X-1)²=3(5X-1)
3.(2X-5)²-(X+4)²=0 展开
1.X²-7X+6=0
2.(5X-1)²=3(5X-1)
3.(2X-5)²-(X+4)²=0 展开
展开全部
1.X²-7X+6=0
(x-1)(x-6)=0
x-1=0,x-6=0
x=1, x=6
2.(5X-1)²=3(5X-1)
(5X-1)²-3(5X-1)=0
(5X-1)(5X-1-3)=0
5X-1=0,5X-4=0
x=0.2,x=0.8
3.(2X-5)²-(X+4)²=0
(2X-5+X+4)(2X-5-x-4)=0
3x-1=0,x-9=0
x=1/3,x=9
(x-1)(x-6)=0
x-1=0,x-6=0
x=1, x=6
2.(5X-1)²=3(5X-1)
(5X-1)²-3(5X-1)=0
(5X-1)(5X-1-3)=0
5X-1=0,5X-4=0
x=0.2,x=0.8
3.(2X-5)²-(X+4)²=0
(2X-5+X+4)(2X-5-x-4)=0
3x-1=0,x-9=0
x=1/3,x=9
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
(X-1)(X-6)=0
(5X-1)(5X-4)=0
(3X-1)(X-9)=0
(5X-1)(5X-4)=0
(3X-1)(X-9)=0
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询