化简：1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)
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1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)
=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)
=1/(x+1)-1/(x+4)
=[(x+4)-(x+1)]/(x+1)(x+4)
=3/(x+1)(x+4)
=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)
=1/(x+1)-1/(x+4)
=[(x+4)-(x+1)]/(x+1)(x+4)
=3/(x+1)(x+4)
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