Question

已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1，求4x/4x2-1/2x+y的值，要详细点的过程

题目有点错了，是[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]÷4y=1，求4x/4x的平方-1/2x+y的值还是用中文吧，求[（4x的平方-y的平方）分之4x]-[(2x+y)分之1]的值

Answer 1

[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1; [x²+y²-(x²-2xy+y²)+2xy-2y²]÷4y=1;(4xy-2y²)÷4y=1; 2y(2x-y)÷4y=1; 2x-y=2; 求：4x÷(4x²-y²)-1÷(2x+y)=4x÷(2x+y)(2x-y)-(2x-y)÷(2x+y)(2x-y)=1÷(2x-y)=0.5

Answer 2

原式=(x²+y²-x²+2xy-y²+2xy-2y²)÷4y
=（4xy-2y²)÷4y
=x-y/2=1
2x-y=2

你能不能把求的写清楚

Answer 3

呵呵，你中英文都有

Answer 4

4x/4x2-1/2x+y，打错了吧