Question

求一道三角函数题

sin130°(1+根号3tan190°)=？求写下详细内容

Answer 1

sin130(1+ sqrt(3) tan190)
=sin130/cos190 (cos190+ sqrt(3) sin190)
=2*sin130/cos190 (sin(30+190))
=2*sin50/(-cos10)*(-sin40)
=2*cos40/cos10*sin40
=sin80/cos10
=1