Question

（1）/（x-3）+2=（4-x）/(3-x)

解分式方程（答案是不成立。但我不知道过程、请教一下啊）

Answer 1

（1）/（x-3）+2=（4-x）/(3-x) 两边乘x-3
1+2(x-3)=x-4
2x-5=x-4
2x-x=5-4
x=1

Answer 2

（1）/（x-3）+2=（4-x）/(3-x)
(1+2x-2*3)/(x-3)=(4-x)/(3-x)
(3-x)(1+2x-2*3)=(x-3)(4-x)
(3-x)(2x-5)=(x-3)(4-x)
6x-2x^2-15+5x=4x-x^2-12-3x
11x-2x^2-15=x-x^2-12
10x=x^2+3
x^2-10x+5^2=-3+5^2
(x-5)^2=22
x-5=根号22
x1=根号22+5
x2=5-根号22