Question

一个装满稻谷的粮囤，上面是圆锥体，下面是圆柱体。量得圆柱底面的周长是62.8米，高2米，圆锥的高是1.2米

要算式

Answer 1

半径R=62.8÷3.14÷2=10米，粮囤的底面积S=3.14×10×10=314平方米
粮囤的容积V=314×2+314×1.2÷3=753.6立方米
重量：753.6×0.05=37.68吨。

Answer 2

周长=2×3.14×r,所以半径r=10m,圆柱体积V=SH=2×3.14×10×10×2=1256立方米，圆锥体积=1/3SH=1/3×2×3.14×10×10×1.2=502.4立方米。

Answer 3

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