Question

C语言编程题 -5<x<0, y=x; x=0, y=x-1; 0<x<10,y=x+1; 要求使用switch语句。

就是个分段函数求解

Answer 1

switch语句对应离散参数，对此例并不适用，除非你的X限定为了整型，建议用if else if else控制。像那个楼上的，基本上错误一大堆······

#include<stdio.h>
int main(void)
{
float x,y;
scanf("%f",x);
if(x>-5&&x<0)
{
y=x;
printf("y=%.2f\n",y);
}
else if(x==0)
{
y=x-1;
printf("y=%.2f\n",y);
}
else if(x>0&&x<10)
{
y=x+1;
printf("y=%2f\n",y);
}
else
{
printf("error date\n");
}
}

Answer 2

#include<stdio.h>
int main()
{
int x,y;
scanf("%d",&x);
swich('x')
{
case"x>-5&&x<0":y=x:break;
case"x=0":y=x:break;
case"x>0&&x<10":y=x+1:break;
default:printf("errior\n"):break;
}
printf("y=%d\n",y);
return 0;
}
内部存在一些符号错误，自己改下。

Answer 3

#include<stdio.h>/* -5<x<0, y=x; x=0, y=x-1; 0<x<10,y=x+1; */
void main()
{
int a;
float x,y;
scanf("%f",&x);
if(x>-5&&x<0)
a=1;
else if(x==0)
a=2;
else if(x>0&&x<10)
a=3;
else
printf("错误\n");
switch(a)
{
case 1:y=x;printf("y=%.1f\n",y);break;
case 2:y=x-1;printf("y=%.1f\n",y);break;
case 3:y=x+1;printf("y=%.1f\n",y);break;
default:break;
}

}

Answer 4

#include<stdio.h>
void main()
{
int x,y;
scanf("%d",&x);
switch(x)
{
case -4:
case -3://都执行y=x
case -2:
case -1:
y=x;break;
case 0:
y=x-1;
break;
case 1:
case 2:
case 3:
case 4:
case 5:
case 6:
case 7:
case 8:
case 9:
y=x+1;
break;
}
printf("y=%d",y);
}

Answer 5

switch(x)
{
case:
}