Question

用C++编一个程序，输入球的半径求一个球的表面积，质量，体积，能给我源代码就好了。

很急啊

Answer 1

#include <iostream>
#include <math.h>

#define pi 3.1415926

同学，求质量必须有密度

#include <iostream>
#include <math.h>

#define pi 3.1415926

void main()
{
double radius = 0;
double density = 0;
std::cout << "半径：";
std::cin >> radius;
std::cout << "密度：";
std::cin >> density;
double area = 4 * pi * pow(radius, 2);
std::cout << "表面积：" << area << std::endl;
double volume = 4 * pi * pow(radius, 3);
std::cout << "体积：" << volume << std::endl;
double quality = density * volume;
std::cout << "质量：" << quality << std::endl;
}

追问

不好意思，密度是7.8kg/m3

Answer 2

#include<iostream>
using namespace std;
void main()
{
float const pi=3.14;
float r,S,V;
cout<<"请输入球的半径";
cin>>r;

S=4*pi*r*r;
V=4/3*pi*r*r*r;
cout<<"球的表面积为"<<S<<endl;
cout<<"球的体积为"<<V<<endl;

}

Answer 3

#include <stdio.h>
int main()
{
float r,s,v,pi=3.14;
printf("请输入半径：\n");
scanf("%f",&r);
s=4*pi*r*r;
v=4*pi*r*r*r/3;
printf("圆球的表面积是:%f\n",s);
printf("圆球的体积是:%f\n",v);
}