数学题1111
2(x+1)^2-1/2(x+2)(x-2)(2a+1)^2(2a-1)^2(x-2)(x+2)-(x-1)(x-3)(2a+1)^2-(2a^2+1)(x+y+1)(x...
2(x+1)^2- 1/2(x+2)(x-2)
(2a+1)^2(2a-1)^2
(x-2)(x+2)-(x-1)(x-3)
(2a+1)^2-(2a^2+1)
(x+y+1)(x+y-1)
(2x-y+c)(-y-c-2x) 展开
(2a+1)^2(2a-1)^2
(x-2)(x+2)-(x-1)(x-3)
(2a+1)^2-(2a^2+1)
(x+y+1)(x+y-1)
(2x-y+c)(-y-c-2x) 展开
1个回答
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2(x+1)^2- 1/2(x+2)(x-2)此题没错？
(2a+1)^2(2a-1)^2=【(2a+1)(2a-1)】^2=(4a^2-1)^2=16a^4-8a^2+1
(x-2)(x+2)-(x-1)(x-3)=x^2-4-(x^2-4x+3）=4x-7
(2a+1)^2-(2a^2+1)=4a^2+4a+1-2a^2-1=2a^2+4a
(x+y+1)(x+y-1)=(x+y)^2-1=x^2+2xy+y^2-1
(2x-y+c)(-y-c-2x)=-(2x-y+c)(y+c+2x)=-(2x+c)^2+y^2=-4x^2-c^2-4cx+y^2
(2a+1)^2(2a-1)^2=【(2a+1)(2a-1)】^2=(4a^2-1)^2=16a^4-8a^2+1
(x-2)(x+2)-(x-1)(x-3)=x^2-4-(x^2-4x+3）=4x-7
(2a+1)^2-(2a^2+1)=4a^2+4a+1-2a^2-1=2a^2+4a
(x+y+1)(x+y-1)=(x+y)^2-1=x^2+2xy+y^2-1
(2x-y+c)(-y-c-2x)=-(2x-y+c)(y+c+2x)=-(2x+c)^2+y^2=-4x^2-c^2-4cx+y^2
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