(x四次方-8x平方y平方+16y四次方)÷(2y+x)平方÷(x-2y)平方等于多少？ 请好心人说一下过程，半小时内完成
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(x^4-8x^2y^2+16y^4))÷(2y+x)^2÷(x-2y)^2
=(x^2-4y^2)^2÷(2y+x)^2÷(x-2y)^2
=[(x^2-4y^2)]^2÷(2y+x)^2÷(x-2y)^2
=[(x-2y)(x+2y)]^2÷(2y+x)^2÷(x-2y)^2
=(x-2y)^2(x+2y)^2÷(2y+x)^2÷(x-2y)^2
=(x-2y)^2÷(x-2y)^2
=1
=(x^2-4y^2)^2÷(2y+x)^2÷(x-2y)^2
=[(x^2-4y^2)]^2÷(2y+x)^2÷(x-2y)^2
=[(x-2y)(x+2y)]^2÷(2y+x)^2÷(x-2y)^2
=(x-2y)^2(x+2y)^2÷(2y+x)^2÷(x-2y)^2
=(x-2y)^2÷(x-2y)^2
=1
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解答：
(x^4-8x^2y^2+16y^4)÷(2y+x)^2÷(x-2y)^2
=(x^2-4y^2)^2÷(2y+x)^2÷(x-2y)^2
=[(x+2y)^2*(x-2y)^2]÷(2y+x)^2÷(x-2y)^2
=1
(x^4-8x^2y^2+16y^4)÷(2y+x)^2÷(x-2y)^2
=(x^2-4y^2)^2÷(2y+x)^2÷(x-2y)^2
=[(x+2y)^2*(x-2y)^2]÷(2y+x)^2÷(x-2y)^2
=1
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