Question

(x四次方-8x平方y平方+16y四次方)÷(2y+x)平方÷(x-2y)平方等于多少？ 请好心人说一下过程，半小时内完成

Answer 1

(x^4-8x^2y^2+16y^4))÷(2y+x)^2÷(x-2y)^2
=(x^2-4y^2)^2÷(2y+x)^2÷(x-2y)^2
=[(x^2-4y^2)]^2÷(2y+x)^2÷(x-2y)^2
=[(x-2y)(x+2y)]^2÷(2y+x)^2÷(x-2y)^2
=(x-2y)^2(x+2y)^2÷(2y+x)^2÷(x-2y)^2
=(x-2y)^2÷(x-2y)^2
=1

Answer 2

解答：

(x^4-8x^2y^2+16y^4)÷(2y+x)^2÷(x-2y)^2
=(x^2-4y^2)^2÷(2y+x)^2÷(x-2y)^2
=[(x+2y)^2*(x-2y)^2]÷(2y+x)^2÷(x-2y)^2
=1