
先化简,再求值:【2x(x的平方y-xy的平方)+xy(xy-x的平方)】,其中x=2008,y=2004
1个回答
展开全部
2x(x^2y-xy^2)+xy(xy-x^2)
=2x^2y(x-y)_x^2y(x-y)
=x^2y(x-y)
=32321025024
初步判断你的题抄错了
=2x^2y(x-y)_x^2y(x-y)
=x^2y(x-y)
=32321025024
初步判断你的题抄错了
追问
对对...应是:【2x(x的平方y-xy的平方)+xy(xy-x的平方)】 除以(x的平方y)
追答
2x(x^2y-xy^2)+xy(xy-x^2)/(x^2y)
=2x^2y(x-y)_x^2y(x-y)/(x^2y)
=x^2y(x-y)/(x^2y)
=x-y
=4
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