Question

谁能帮我写一个JSP分页的SQL语句,进行详解一下啊!

Answer 1

建立表：
CREATE TABLE [TestTable] (
[ID] [int] IDENTITY (1, 1) NOT NULL ,
[FirstName] [nvarchar] (100) COLLATE Chinese_PRC_CI_AS NULL ,
[LastName] [nvarchar] (100) COLLATE Chinese_PRC_CI_AS NULL ,
[Country] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[Note] [nvarchar] (2000) COLLATE Chinese_PRC_CI_AS NULL
) ON [PRIMARY]
GO

插入数据：(100万条)
SET IDENTITY_INSERT TestTable ON
declare @i int
set @i=1
while @i<=1000000
begin
insert into TestTable([id], FirstName, LastName, Country,Note) values(@i, 'FirstName_XXX','LastName_XXX','Country_XXX','Note_XXX')
set @i=@i+1
end
SET IDENTITY_INSERT TestTable OFF

------------------------------------
分页方案一：(利用Not In和SELECT TOP分页)

当前页数从0编号

(默认ASC排序)
//当前页数=0时用SQL：
SELECT TOP 每页记录数 *
FROM TestTable
ORDER BY ID

//当前页数>0时用SQL：
SELECT TOP 每页记录数 *
FROM TestTable
WHERE (ID NOT IN
(SELECT TOP 每页记录数*当前页数 id //当前页数必须>0
FROM TestTable
ORDER BY id))
ORDER BY ID
**************************
用DESC排序时，需要改成：
//当前页数=0时用SQL：
SELECT TOP 每页记录数 *
FROM TestTable
ORDER BY ID DESC

//当前页数>0时用SQL：
SELECT TOP 每页记录数 *
FROM TestTable
WHERE (ID NOT IN
(SELECT TOP 每页记录数*当前页数 id //当前页数必须>0
FROM TestTable
ORDER BY id DESC))
ORDER BY ID DESC
-------------------------------------
分页方案二：(利用ID大于多少和SELECT TOP分页）效率最高！严重推荐

当前页数从0编号

(默认ASC排序)
SELECT TOP 每页记录数 *
FROM TestTable
WHERE (ID >=
(SELECT MAX(id)
FROM (SELECT TOP (每页记录数*当前页数)+1 id //当前页数从0编号
FROM TestTable
ORDER BY id) AS T))
ORDER BY ID
*************************
用DESC排序时，需要改成：
SELECT TOP 每页记录数 *
FROM TestTable
WHERE (ID <=
(SELECT MIN(id)
FROM (SELECT TOP (每页记录数*当前页数)+1 id //当前页数从0编号
FROM TestTable
ORDER BY id DESC) AS T))
ORDER BY ID DESC
================================================
不管用哪种方法,设置条件都在最里面的select里
如:
把id>=100 且 FirstName='FirstName_XXX'的记录分页
(默认ASC排序)
SELECT TOP 每页记录数 * FROM TestTable
WHERE (ID >=
(SELECT MAX(id)
FROM (SELECT TOP (每页记录数*当前页数)+1 id //当前页数从0编号
FROM TestTable
where id >=100 and FirstName='FirstName_XXX' //设置条件
ORDER BY id) AS T))
ORDER BY ID

Answer 2

推荐参考《jsp从入门到精通》，里面有jsp分页实例

Answer 3

oracle : select * from table where rownum > [page] * [item_count_per_page] and rownum < [page+1] * [item_count_per_page]
sqlserver : select top [item_count_per_page] * from table where id > [page] * [item_count_per_page]*[step] order by id(此方法前提是id自动增长，且增长大小为step）
mySql : select * from table limit [page] * [item_count_per_page],[item_count_per_page]
sybase与sqlserver类似