Question

c++编程问题，急求答案啊！！！

写一个简单程序模拟掷骰子(dice)游戏，掷一次骰子可能随机得到1，2，3，4，5，6中任意一个数，一个人可以掷两次，要求程序计算出两次的平均值：输出结果如下：
The first die comes up 3
The second die comes up 5
Your total roll is 8

Answer 1

#include<iostream>

#include <time.h> 

using namespace std;

#define DiceMax 6

#define DiceTime 2

unsigned FirstDice,SecondDice,Total;

double Average;

void InitDice(){

 srand(time(NULL)); 

 cout<<"=============Start Dicing:============="<<endl;

}

unsigned Dice (){

 return rand()%DiceMax  + 1;

}

double CacularAver(unsigned DicingTime ){

 return (Total = ((FirstDice = Dice() ) + (SecondDice = Dice()))) / DicingTime ;

}

void Display(unsigned FirstDice,unsigned SecondDice,unsigned Total,double Average){

 cout<<"The first die comes up "<<FirstDice<<endl;

 cout<<"The second die comes up"<<SecondDice<<endl;

 cout<<"Your total roll is "<<Total<<endl;

 cout<<"Your Average roll is "<<Average<<endl;

}

int main(){

    char Continute = 'y';

    InitDice();

    do{

 Display(FirstDice,SecondDice,Total,Average = CacularAver( DiceTime ));

 cout<<"Continute?(y/n):";

 cin>>Continute;

    }while(Continute == 'y' || Continute == 'Y');

    cout<<"===========Dicing End============="<<endl;

    return 0;

}

Answer 2

#include <stdlib.h>
#include <stdio.h>
#include<conio.h>
#include <time.h>

int main(void)
{
int i=2 ,h=5;
int r,s,j,d,y;

int sz[10]={1,2,3,4,5,6};
srand(time(NULL));

r=rand()%(10-i);

printf("The first die comes up %d\n",sz[r]);
y=sz[r];

for( j=r;j<10;j++)
sz[j]=sz[j+1];

s=rand()%(10-h);

printf(" The second die comes up %d\n",sz[s]);
printf("Your total roll is %d\n",y+sz[s]);

for(d=s;d<10;d++)
sz[d]=sz[d+1];

getch();
return 0;
}

Answer 3

这个都问，你还想学编程么？

追问

不会就要问啊