Question

2(a-1)²-12(a-1)+18

分解因式

Answer 1

提示：把a-1看做整体。

2(a-1)²-12(a-1)+18
=2[(a-1)²-6(a-1)+9]
=2[(a-1)-3]²
=2(a-4)²

Answer 2

2(a-4)²

Answer 3

2(a-1)²-12(a-1)+18
=[2(a-1)-6][(a-1)-3]
=(2a-8)(a-4)
=2(a-4)^2