1-(x-1/(1-x))²÷(x²-x+1)/(x²-2x+1)
2个回答
展开全部
1-｛x-【1/(1-x)】｝²÷（x²-x+1)/(x²-2x+1)
=1-[(x-x^2-1)/(1-x)]^2*(x-1)^2/(x^2-x+1)
=1-[(x^2-x+1)^2/(x-1)^2]*(x-1)^2/(x^2-x+1)
=1-(x^2-x+1)
=-x^2+x
=1-[(x-x^2-1)/(1-x)]^2*(x-1)^2/(x^2-x+1)
=1-[(x^2-x+1)^2/(x-1)^2]*(x-1)^2/(x^2-x+1)
=1-(x^2-x+1)
=-x^2+x
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
｛x-【1/(1-x)】｝=x(x-1)/(x-1)+1/(x-1)=【x(x-1)+1】/(x-1)
（x²-x+1)/(x²-2x+1)=)=【x(x-1)+1】/(x-1)^2所以
｛x-【1/(1-x)】｝²÷（x²-x+1)/(x²-2x+1)=｛【x(x-1)+1】/(x-1) ｝² * (x-1)^2/【x(x-1)+1】=1
所以1-1=0
····
（x²-x+1)/(x²-2x+1)=)=【x(x-1)+1】/(x-1)^2所以
｛x-【1/(1-x)】｝²÷（x²-x+1)/(x²-2x+1)=｛【x(x-1)+1】/(x-1) ｝² * (x-1)^2/【x(x-1)+1】=1
所以1-1=0
····
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
