Question

如图,△ABC中,AD平分∠BAC,BE⊥AC于点E,交AD于点P,试说明∠2=二分之一(∠ABC+∠C)

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Answer 1

∠2=90°-∠PAE ①
∠PAE=∠BAD ②

∠BAD=∠ADC-∠ABC
∠ADC=180°-∠DAC-∠C
=180°-∠BAD-∠C
联立得∠BAD=90-1/2(∠ABC+∠C) ③

再联立①②③得∠2=1/2(∠ABC+∠C)

Answer 2

∠2是指哪个角？