分解因式(a+b)^2(a-b)^2-a^4+b^4
3个回答
展开全部
(a+b)^2(a-b)^2-a^4+b^4
=(a²-b²)²-a^4+b^4
=a^4+b^4-2a²b²-a^4+b^4
=2b^4-2a²b²
=2b²(b²-a²)
=2b²(b+a)(b-a)
=(a²-b²)²-a^4+b^4
=a^4+b^4-2a²b²-a^4+b^4
=2b^4-2a²b²
=2b²(b²-a²)
=2b²(b+a)(b-a)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
(a+b)²(a—b)²—a^4+b^4
= (a+b)²(a—b)²+b^4—a^4
= (a+b)²(a—b)²(b²+a²)(b²—a²)
= (a+b)²(a—b)²(b²+a²)(b+a)(b—a)
=(a+b)³(b²+a²)(a—b)²〔—(a—b)〕
=—(b²+a²)(a+b)³(a—b)³
= (a+b)²(a—b)²+b^4—a^4
= (a+b)²(a—b)²(b²+a²)(b²—a²)
= (a+b)²(a—b)²(b²+a²)(b+a)(b—a)
=(a+b)³(b²+a²)(a—b)²〔—(a—b)〕
=—(b²+a²)(a+b)³(a—b)³
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询