Question

用简便方法算3道数学题！

1. 3又1/7×（3又1/7-7又1/3)×7/22÷1又1/22
2. (3/5-1/2-7/12)×（60×3/7-60×1/7+60×5/7)
3. (-12)÷[（-16）+40+（-8）]
第一题你们都算错了，是-4，所以关闭问题

Answer 1

第一题： 3又1/7×（3又1/7-7又1/3)×7/22÷1又1/22= [（3又1/7）^2-1]×7/22÷1又1/22=(3又1/7-7/22)÷1又1/22=22^2/(7*23)-7/23=(22^2-7^2)/(23*7)=(29*15)/(23*7)=435/161
第二题： (3/5-1/2-7/12)×（60×3/7-60×1/7+60×5/7)=(3/5-1/2-7/12)×[60×(3/7-1/7+5/7)]=(3/5-1/2-7/12)×60=36-30-35=-29
第三题： (-12)÷[（-16）+40+（-8）]=(-12)÷16=-3/4

Answer 2

1.3又1/7乘以（3乘以1/7减7又1/3）7/22除以1又1/22
=22/7乘以（22/7减22/3）乘以7/22除以23/22
=22/7乘以（-88/21）乘以7/22除以23/22
=-13又25/147乘以7/22乘以22/23
=-4又4/483
剩下两题明天给你好吗？

Answer 3

1,3又1/7×（3又1/7-7又1/3)×7/22÷1又1/22
=22/7×7/22×（3又1/7-7又1/3)÷1又1/22
=（3又1/7-7又1/3)÷1又1/22
=（3又1/7-7又1/3）×22/23
=-4又4/21×22/23
=-4又88/483
2.(3/5-1/2-7/12)×（60×3/7-60×1/7+60×5/7)
=(3/5-1/2-7/12)×60×(3/7-1/7+5/7)
=(3/5-1/2-7/12)×60×1
=3/5×60-1/2×60-7/12×60
=36-30-35
=-29
3. (-12)÷[（-16）+40+（-8）]
= (-12)÷16
=-3/4

Answer 4

(1)22/7*7/22*（3又1/7-7又1/3)*23/22
=*（3又1/7-7又1/3)*23/22
=22/7*23/22-22/3*23/22
=23/7-23/3
=-92/21
(2)(3/5-1/2-7/12)*（60*3/7-60*1/7+60*5/7)
=(3/5-1/2-7/12)*[60*(3/7-1/7+5/7)]
=(3/5-1/2-7/12)*60
=-29
(3)-(12/16)=-3/4

Answer 5

1)22/7*7/22*（3又1/7-7又1/3)*23/22
=22/7*23/22-22/3*23/22
=23/7-23/3
=-92/21
(2)(3/5-1/2-7/12)*（60*3/7-60*1/7+60*5/7)
=(3/5-1/2-7/12)*[60*(3/7-1/7+5/7)]
=(3/5-1/2-7/12)*60
=-29
(3)-(12/16)=-3/4