
数学题!!!快点
计算:3.2^(1+log2^3)=?2^(1-log2^3)=?4.log2^(7/5)+log2(5/7)=?log2^28-log2^7=?...
计算:
3. 2^(1+log2^3)=?
2^(1-log2^3)=?
4.log2^(7/5)+log2(5/7)=?
log2^28-log2^7=? 展开
3. 2^(1+log2^3)=?
2^(1-log2^3)=?
4.log2^(7/5)+log2(5/7)=?
log2^28-log2^7=? 展开
2个回答
展开全部
3.原式=2*2^log2^3=2*3=6
同理等于2/3
4.=log2^(7/5)*(5/7)=log2^1=0
=log2^(28/7)=log2^4=2
同理等于2/3
4.=log2^(7/5)*(5/7)=log2^1=0
=log2^(28/7)=log2^4=2
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