Question

C语言，如何给下面代码加一个是否继续计算Y/N?

C语言，如何给下面代码加一个是否继续计算Y/N?
在程序运行完毕之后，给与提示：是否继续计算Y/N? 如果Y就继续从头开始重新计算。记住，重新计算的数据必须正确.答的好可以追加20分
#include<stdio.h>
void main()
{
char a,ch;
int zongshu=0,zimu=0,shuzi=0,zifu=0;
printf("请输入一行字符:\n");
do
{
a=getchar();
printf("");
zongshu++;
if(a>='a'&&a<='z'||a>='A'&&a<='Z')
zimu++;
else if(a>='0'&&a<='9')
shuzi++;
else
zifu++;
}
while(a!='\n');
printf("字母数:%d\n数字数:%d\n字符数:%d\n总数是:%d\n",zimu,shuzi,--zifu,--zongshu);

}

Answer 1

我没有对你的程序进行检测,直接在原程序基础上加的代码!!!

char a,ch,Opear;
while(1==1)//一直循环
{
int zongshu=0,zimu=0,shuzi=0,zifu=0;
printf("请输入一行字符:\n");
do
{
a=getchar();
printf("");
zongshu++;
if(a>='a'&&a<='z'||a>='A'&&a<='Z')
zimu++;
else if(a>='0'&&a<='9')
shuzi++;
else
zifu++;
}
while(a!='\n');
printf("字母数:%d\n数字数:%d\n字符数:%d\n总数是:%d\n",zimu,shuzi,--zifu,--zongshu);

printf("是否继续计算Y/N?");
Opear=getchar();
if (Opear<>'Y')//用户输入非'Y'字符退出
break;
}

Answer 2

#include<stdio.h>
void jszf()
{
char a,ch;
int zongshu=0,zimu=0,shuzi=0,zifu=0;
printf("请输入一行字符:\n");
do
{
a=getchar();
printf("");
zongshu++;
if(a>='a'&&a<='z'||a>='A'&&a<='Z')
zimu++;
else if(a>='0'&&a<='9')
shuzi++;
else
zifu++;
}
while(a!='\n');
printf("字母数:%d\n数字数:%d\n字符数:%d\n总数是:%d\n",zimu,shuzi,--zifu,--zongshu);
}
void main()
{
char yorn;
do
{
jszf();
do
{
printf("是否继续计算Y/N?");
yorn=getch();
printf("%c\n",yorn);
}
while (yorn!='y' && yorn!='Y' && yorn!='n' && yorn!='N');
}
while (yorn=='y' || yorn=='Y');
}

Answer 3

#include<stdio.h>

int main()
{
char select;
do{
char a,ch;
int zongshu=0,zimu=0,shuzi=0,zifu=0;
printf("请输入一行字符:\n");
do
{
a=getchar();
printf("");
zongshu++;
if(a>='a'&&a<='z'||a>='A'&&a<='Z')
zimu++;
else if(a>='0'&&a<='9')
shuzi++;
else
zifu++;
}while(a!='\n');
printf("字母数:%d\n数字数:%d\n字符数:%d\n总数是:%d\n",zimu,shuzi,--zifu,--zongshu);
printf("是否继续?(Y/N): ");
scanf("%c", &select);
}while(select != 'n' && select != 'N');
}