
计算:(2+1)(2的平方+1)(2的4次方+1)(2d的8次方+1)(2的16次方+1)(2的32次方+1)
2个回答
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(2+1)(2^2+1)(2^4+1)...(2^32+1) 【2^2是2的2次方,2^4是2的4次方,其他则以此类推】
=(2-1)(2+1)(2^2+1)(2^4+1)...(2^32+1)
=(2^2-1)(2^2+1)(2^4+1)...(2^32+1)
=(2^4-1)(2^4+1)...(2^32+1)
=...
=(2^32-1)(2^32+1)
=2^64-1
=(2-1)(2+1)(2^2+1)(2^4+1)...(2^32+1)
=(2^2-1)(2^2+1)(2^4+1)...(2^32+1)
=(2^4-1)(2^4+1)...(2^32+1)
=...
=(2^32-1)(2^32+1)
=2^64-1
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