Question

java程序：任意输入一个4*4矩阵，实现输出并计算其中元素之和。

Answer 1

import javax.swing.JOptionPane;
public class sumMatrix {
public static void main(String[] args) {

JOptionPane.showMessageDialog(null, "Enter a 4 by 4 matrix row by row:");

int[][] matrix = new int[4][4];

for (int i = 0; i < matrix.length; i++)
for (int j = 0; j < matrix[i].length; j++)
matrix[i][j] = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter an integer for the matrix.");

JOptionPane.showMessageDialog(null, "Sum of the Matrix is " + sumMatrix(matrix));
// double sum = sumMatrix(matrix);
}
public static double sumMatrix(int[][] m) {
int sum = 0;

for (int i = 0; i < m.length; i++)
for (int j = 0; j < m[i].length; j++)
sum = sum + m[i][j];

return sum;
}
}

追答

亲，记得采纳哦

Answer 2

一个矩阵就是一个二维数组，用二维数组接收数据，用双层for循环累加，搞定

Answer 3

早忘了

Answer 4

引用pieryon的回答：
import javax.swing.JOptionPane;
public class sumMatrix {
public static void main(String[] args) {

JOptionPane.showMessageDialog(null, "Enter a 4 by 4 matrix row by row:");

int[][] matrix = new int[4][4];

for (int i = 0; i < matrix.length; i++)
for (int j = 0; j < matrix[i].length; j++)
matrix[i][j] = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter an integer for the matrix.");

JOptionPane.showMessageDialog(null, "Sum of the Matrix is " + sumMatrix(matrix));
// double sum = sumMatrix(matrix);
}
public static double sumMatrix(int[][] m) {
int sum = 0;

for (int i = 0; i < m.length; i++)
for (int j = 0; j < m[i].length; j++)
sum = sum + m[i][j];

return sum;
}
}

matrix[i][j] = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter an integer for the matrix.")）;