Question

数学七年级

(—1/2m^3n)^3乘（-2m^2n)^4=
-10a^2c(-1/6ab^2)-1/3bc乘5a^3b=
(x-3)(x^2+3x）+（x+3)(x^2-3x)=
要过程

Answer 1

(—1/2m^3n)^3乘（-2m^2n)^4=-1/8m^6n^3乘16m^8n^4=-2m^14n^7
-10a^2c(-1/6ab^2)-1/3bc乘5a^3b=5/3a^3b^2c-5/3a^3b^2c=0
(x-3)(x^2+3x）+（x+3)(x^2-3x)=(x-3)x(x+3)+(x+3)x(x-3)=2x(x+3)(x-3)

Answer 2

(-1/2m^3n)^3乘（-2m^2n)^4
=-1/8m^(9n)*16m^(8n)
=(-1/8*16)*m^(9n+8n)
=-2m^(17n)

-10a^2c(-1/6ab^2)-1/3bc乘5a^3b
=5/3a³b²c-5/3a³b²c
=0

(x-3)(x²+3x）+（x+3)(x²-3x)
=(x-3)*x(x+3)+(x+3)*x(x-3)
=2x(x-3)(x+3)
=2x(x²-9)
=2x³-18x

Answer 3

(—1/2m^3n)^3乘（-2m^2n)^4
=-1/8m^(9n)*8m^(8n)
=(-1/8*8)*m^(9n+8n)
=-m^(17n)

-10a^2c(-1/6ab^2)-1/3bc乘5a^3b
=5/3a^3b^2c-1/3a^3b^2c
=4/3a^3b^2c

(x-3)(x^2+3x）+（x+3)(x^2-3x)
=(x-3)*x(x+3)+(x+3)*x(x-3)
=2x(x-3)(x+3)
=2x(x^2-9)
=2x^3-18x

Answer 4

(—1/2m^3n)^3乘（-2m^2n)^4=(-1/8*m^9n)*(16*m^8n)=-2m^17n

-10a^2c(-1/6ab^2)-1/3bc乘5a^3b=5/3a^3 b^2 c-5/3a^3 b^2 c=0
(x-3)(x^2+3x）+（x+3)(x^2-3x)=x(x-3)(x+3)+x(x-3)(x+3)=2x^3-18X

Answer 5

(-1/2m^3n)^3x（-2m^2n)^4
=-1/8m^(9n)*16m^(8n)
=(-1/8*16)*m^(9n+8n)
=-2m^(17n)
-10a^2c(-1/6ab^2)-1/3bcx5a^3b
=5/3a³b²c-5/3a³b²c
=0
(x-3)(x²+3x）+（x+3)(x²-3x)
=(x-3)*x(x+3)+(x+3)*x(x-3)
=2x(x-3)(x+3)
=2x(x²-9)
=2x³-18x