Question

用配方法解一元二次方程:2x²+1=3x

用配方法解一元二次方程:2x²+1=3x
要过程.!!!!

Answer 1

2x²+1=3x
则x²-3/2x+1/2=0
x²-2*3/4*x+(3/4)²=(3/4)²-1/2
(x-3/4)²=1/16
则x-3/4=±1/4
所以x=1或x=1/2

Answer 2

2x²+1=3x
2x²-3x+1=0
-2 1
-1 1
..................
-2x+1=0
-x+1=0
解得:x=1/2或x=1

Answer 3

2 x2 -3x+1=0
2 (x-3/4)2 =1/8
x-3/4=1/4或-1/4
x=1或1/2

Answer 4

2x²+1=3x 2x²-3x+1=0 2(x²-3/2x+1/2) =0 2[x²-2*3/4x+(3/4)^2-1/2+(3/4)^2]=0
(x-3/4)^2=1/16 x-3/4=±1/4 x=3/4±1/4

Answer 5

由2x²+1=3x得
2x²-3x-1=0
得（x-1)（2x-3）=0
所以x=1或x=2/3

Answer 6

X=0.5