
已知:1/X+1/Y=4,求2X+XY+2Y/3X-4XY+3Y的值? “/”为÷
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1/X+1/Y=4
(X+Y)/XY=4
X+Y=4XY
(2X+XY+2Y)/(3X-4XY+3Y)
=[2(X+Y)+XY]/[3(X+Y)-4XY]
=[2*4XY+XY]/[3*4XY-4XY]
=9XY/(8XY)
=9/8
(X+Y)/XY=4
X+Y=4XY
(2X+XY+2Y)/(3X-4XY+3Y)
=[2(X+Y)+XY]/[3(X+Y)-4XY]
=[2*4XY+XY]/[3*4XY-4XY]
=9XY/(8XY)
=9/8
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