[(x+y)(x-y)-(x-y)的平方+2y(x-y)]除以(4y)请帮我一下写两道计算题
[(x+y)(x-y)-(x-y)的平方+2y(x-y)]除以(4y)[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以(4x)...
[(x+y)(x-y)-(x-y)的平方+2y(x-y)]除以(4y)
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以(4x) 展开
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以(4x) 展开
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[(x+y)(x-y)-(x-y)^2+2y(x-y)]/(4y)
=[x^2-y^2-(x^2-2xy+y^2)+2xy-2y^2]/(4y)
=(x^2-y^2-x^2+2xy-y^2+2xy-2y^2)
=(4xy-4y^2)/(4y)
=(x-y) (y≠0)
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/(4x)
=[9x^2-4y^2-(5x^2-2xy+10xy-4y^2)]/(4x)
=(9x^2-4y^2-5x^2-8xy+4y^2)/(4x)
=(4x^2-8xy)/(4x)
=x-2y (x≠0)
=[x^2-y^2-(x^2-2xy+y^2)+2xy-2y^2]/(4y)
=(x^2-y^2-x^2+2xy-y^2+2xy-2y^2)
=(4xy-4y^2)/(4y)
=(x-y) (y≠0)
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/(4x)
=[9x^2-4y^2-(5x^2-2xy+10xy-4y^2)]/(4x)
=(9x^2-4y^2-5x^2-8xy+4y^2)/(4x)
=(4x^2-8xy)/(4x)
=x-2y (x≠0)
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[(x+y)(x-y)-(x-y)的平方+2y(x-y)]÷(4y)
=(x-y)[(x+y)-(x-y)+2y]÷(4y)
=(x-y)[x+y-x+y+2y]÷(4y)
=4y(x-y)÷(4y)
=x-y
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷ (4x)
=[(9x平方-4y平方)-(5x平方+8xy-4y平方)]÷ (4x)
=(9x平方-4y平方-5x平方-8xy+4y平方)÷ (4x)
=(4x平方-8xy)÷ (4x)
=4x(x-2y)÷ (4x)
=x-2y
=(x-y)[(x+y)-(x-y)+2y]÷(4y)
=(x-y)[x+y-x+y+2y]÷(4y)
=4y(x-y)÷(4y)
=x-y
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷ (4x)
=[(9x平方-4y平方)-(5x平方+8xy-4y平方)]÷ (4x)
=(9x平方-4y平方-5x平方-8xy+4y平方)÷ (4x)
=(4x平方-8xy)÷ (4x)
=4x(x-2y)÷ (4x)
=x-2y
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