Question

C语言程序设计：编写如下程序

输入一个不多于5位的正整数，要求：

1. 求出它是几位数；
2. 分别输出每一位数字；
3. 按逆序输出各位数字，例如原数为 321，应输出 123。.

Answer 1

#include<stdio.h>
void main()
{
long a,b,c,d,e,x;
scanf("%ld",&x);
a=x/10000;/*分解出万位*/
b=x%10000/1000;/*分解出千位*/
c=x%1000/100;/*分解出百位*/
d=x%100/10;/*分解出十位*/
e=x%10;/*分解出个位*/
if (a!=0){ printf("there are 5, %ld %ld %ld %ld %ld\n",a,b,c,d,e); printf("逆序为, %ld %ld %ld %ld %ld\n",e,d,c,b,a); }
else if (b!=0) {printf("there are 4, %ld %ld %ld %ld\n",b,c,d,e); printf("逆序为, %ld %ld %ld %ld\n",e,d,c,b);}
else if (c!=0) {printf(" there are 3,%ld %ld %ld\n",c,d,e); printf("逆序为, %ld %ld %ld\n",e,d,c);}
else if (d!=0) {printf("there are 2, %ld %ld\n",d,e); printf("逆序为, %ld %ld\n",e,d);}
else if (e!=0) {printf(" there are 1,%ld\n",e); printf("逆序为, %ld\n",e);}
}

Answer 2

main()
{long a;
int i=0,s=0,x;
printf("他的每一位数");
while(a!=0)
{i=i+1;
a=a/10;
s=s*10+x;
printf("%d",x);
}
printf("\n");
printf("他是%d位数\n",i);
printf("他的逆序是%d\n",s);
}

Answer 3

#include <stdio.h>
void main()
{
long inputNumber = -1;
long outputNumber = 0;
int digit;
printf("请输入小于6位的正整数\n");
while(inputNumber < 0 || inputNumber > 99999)
{
scanf("%ld",&inputNumber);
if (inputNumber < 0 || inputNumber > 99999)
{
printf("\n输入数字错误,再试一次\n");
}
}
for (digit = 1; digit<= 5; digit++)
{
outputNumber = outputNumber*10 + inputNumber % 10;
printf("\n%d",inputNumber%10);
inputNumber /= 10;
if (inputNumber == 0)
{
break;
}
}
printf("\n有%ld位",digit);
printf("\n逆序为%ld",outputNumber);
}