Question

c语言问题，求一个输入出生年月日和现在的年月日就可以计算人活了多少天的程序

Answer 1

#include "stdio.h"
struct student
{
int year;
int month;
int day;
};
year(int year)
{
if((year%4==0&&year%100==0)||(year%400==0))
return 1;
else
return 0;
}
month(int n)
{
switch(n)
{
case 1:return 31;
case 2:return 28;
case 3:return 31;
case 4:return 30;
case 5:return 31;
case 6:return 30;
case 7:return 31;
case 8:return 31;
case 9:return 30;
case 10:return 31;
case 11:return 30;
case 12:return 31;
}
}
void main()
{
struct student p1,p2;
int sum=0,i,sumbe=0;
printf("请输入你的出生年、月、日:");
scanf("%d%d%d",&p1.year,&p1.month,&p1.day);
printf("请输入今天的年、月、日:");
scanf("%d%d%d",&p2.year,&p2.month,&p2.day);
for(i=1;i<p1.month;i++)
sumbe=sumbe+month(i);
if(p1.year>2||(p1.month==2&&p1.day==30))
sumbe=sumbe+year(p1.year);
sumbe+=p1.day;
for(i=1;i<p2.month;i++)
sum=sum+month(i);
if(p2.year>2||(p2.month==2&&p2.day==30));
sum=sum+year(p2.year);
sum=sum+365*(p2.year-p1.year);
for(i=p1.year;i<p2.year;i++)
sum=sum+year(i);
sum=sum+year(p2.year);
sum=sum+p2.day;
sum=sum-sumbe;
printf("%d",sum);
getch();

}