Question

c++,用递归调用求1+2+3+4+5+6+7+8+9+10的和

Answer 1

代码如下：
#include <iostream>
using namespace std;

int sum(int n)
{
if (n == 0)
return 0;
return n + sum(n-1);

}

void main()
{
cout<<sum(10)<<endl;

}
不知道有没帮到你 望采纳

Answer 2

#include<iostream>
using namespace std;
int sum(int n)
{
return sum(n-1)+n;
}

int main()
{
cout<<"sum(n)="<<sum(10)<<endl;
return 0;
}

Answer 3

#include <iostream>
using namespace std;

int sum(int n)
{
if (sum <= 0)
return 0;
return 1 + sum(n-1);
}

int main()
{
cout<<sum(10)<<endl;
return 0;
}

追问

错误的！死机了

追答

之前没调试，打错了
#include
using namespace std;

int sum(int n)
{
if (n <= 0)
return 0;
return n + sum(n-1);
}

int main()
{
cout<<sum(10)<<endl;
return 0;
}

Answer 4

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