英语翻译不要用机器
Well,itseemsthefirstproblemistooeasy.Iwillletyouknowhowfoolishyouarelater."feng5166sa...
Well, it seems the first problem is too easy. I will let you know how foolish you are later." feng5166 says.
"The second problem is, given an positive integer N, we define an equation like this:
N=a[1]+a[2]+a[3]+...+a[m];
a[i]>0,1<=m<=N;
My question is how many different equations you can find for a given N.
For example, assume N is 4, we can find:
4 = 4;
4 = 3 + 1;
4 = 2 + 2;
4 = 2 + 1 + 1;
4 = 1 + 1 + 1 + 1;
so the result is 5 when N is 4. Note that "4 = 3 + 1" and "4 = 1 + 3" is the same in this problem. Now, you do it!" 展开
"The second problem is, given an positive integer N, we define an equation like this:
N=a[1]+a[2]+a[3]+...+a[m];
a[i]>0,1<=m<=N;
My question is how many different equations you can find for a given N.
For example, assume N is 4, we can find:
4 = 4;
4 = 3 + 1;
4 = 2 + 2;
4 = 2 + 1 + 1;
4 = 1 + 1 + 1 + 1;
so the result is 5 when N is 4. Note that "4 = 3 + 1" and "4 = 1 + 3" is the same in this problem. Now, you do it!" 展开
3个回答
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Well, it seems the first problem is too easy. I will let you know how foolish you are later." feng5166 says.
噢,第一个问题看起来太简单了,迟点我会让你知道你是多么愚蠢,feng5166说
The second problem is, given an positive integer N, we define an equation like this:
第二个问题是,输入一个正整数N,我们这样定义一条方程式:
N=a[1]+a[2]+a[3]+...+a[m];
a[i]>0,1<=m<=N;
My question is how many different equations you can find for a given N.我的问题是,在一个既定的N的基础上,你能找到多少条不同的方程式
For example, assume N is 4, we can find:
例如,假定N是4,我们可以找到
so the result is 5 when N is 4. Note that "4 = 3 + 1" and "4 = 1 + 3" is the same in this problem. Now, you do it!"
因此,当N是4时,结果是5。注意,“4 = 3 + 1" 和 "4 = 1 + 3" 在这个问题上是一样的。
噢,第一个问题看起来太简单了,迟点我会让你知道你是多么愚蠢,feng5166说
The second problem is, given an positive integer N, we define an equation like this:
第二个问题是,输入一个正整数N,我们这样定义一条方程式:
N=a[1]+a[2]+a[3]+...+a[m];
a[i]>0,1<=m<=N;
My question is how many different equations you can find for a given N.我的问题是,在一个既定的N的基础上,你能找到多少条不同的方程式
For example, assume N is 4, we can find:
例如,假定N是4,我们可以找到
so the result is 5 when N is 4. Note that "4 = 3 + 1" and "4 = 1 + 3" is the same in this problem. Now, you do it!"
因此,当N是4时,结果是5。注意,“4 = 3 + 1" 和 "4 = 1 + 3" 在这个问题上是一样的。
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嗯,看来首先的问题是太容易了。我要让你知道你有多愚蠢以后。”feng5166说。
“第二个问题是,在给定一个正整数N,我们定义一个方程是这样子的:
N =[1][2]+ a +一[3]+…+一[m];
一个[i]> 0、1 < = m < = N;
我的问题是有多少不同的方程的话,你会发现,对于给定的N。
例如,假设N是4,我们可以发现:
4 = 4片;
4 = 3 + 1;
4 = 2 + 2例;
2 + 1 + 4 = 1;
4 = 1 + 1 + 1 + 1;
所以结果是当N为4。值得注意的是,“4 = 3 + 1 "和" 4 = 1 + 3”
“第二个问题是,在给定一个正整数N,我们定义一个方程是这样子的:
N =[1][2]+ a +一[3]+…+一[m];
一个[i]> 0、1 < = m < = N;
我的问题是有多少不同的方程的话,你会发现,对于给定的N。
例如,假设N是4,我们可以发现:
4 = 4片;
4 = 3 + 1;
4 = 2 + 2例;
2 + 1 + 4 = 1;
4 = 1 + 1 + 1 + 1;
所以结果是当N为4。值得注意的是,“4 = 3 + 1 "和" 4 = 1 + 3”
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嗯,看来第一个问题太简单了。等会就让你知道你有多愚蠢。“feng5166”(人名)说道。
第二个问题是,给出一个数列N,问题如下:
N=a[1]+a[2]+a[3]+...+a[m];
a[i]>0,1<=m<=N;
我的问题是,对于给定的N值,你能得出多少个不同的方程。
例如:N是4,我们可以发现:
4 = 4;
4 = 3 + 1;
4 = 2 + 2例;
2 + 1 + 4 = 1;
4 = 1 + 1 + 1 + 1;
所以结果是当N为4。值得注意的是,“4 = 3 + 1 "和" 4 = 1 + 3”,也正是在这个问题上!
好吧,开始。
第二个问题是,给出一个数列N,问题如下:
N=a[1]+a[2]+a[3]+...+a[m];
a[i]>0,1<=m<=N;
我的问题是,对于给定的N值,你能得出多少个不同的方程。
例如:N是4,我们可以发现:
4 = 4;
4 = 3 + 1;
4 = 2 + 2例;
2 + 1 + 4 = 1;
4 = 1 + 1 + 1 + 1;
所以结果是当N为4。值得注意的是,“4 = 3 + 1 "和" 4 = 1 + 3”,也正是在这个问题上!
好吧,开始。
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